CBSE BOARD PYQS · CHAPTER 06
Triangles
CBSE Most Repeated PYQs
Solve official CBSE Previous Year Board Questions (2015-2024) for Triangles. Click on options to test yourself, or click "Show Solution & Answer" for complete step-by-step working.
1 Mark
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If △ABC ~ △DEF and AB/DE = 1/3, then Area(△ABC) / Area(△DEF) is:
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Sides of two similar triangles are in ratio 4 : 9. Areas of these triangles are in ratio:
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A vertical pole of length 6 m casts shadow 4 m long on ground. At same time tower casts shadow 28 m long. Height of tower is:
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Assertion (A): If line divides any two sides of a triangle in same ratio, line is parallel to third side. Reason (R): This statement is known as Converse of Basic Proportionality Theorem.
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Assertion (A): All congruent triangles are similar. Reason (R): All similar triangles are congruent.
2 Marks
In △ABC, DE || BC. AD = x, DB = x-2, AE = x+2, EC = x-1. Find x.
2 Marks
Diagonals of trapezium ABCD with AB || DC intersect at O. Show AO/BO = CO/DO.
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A ladder 10m long reaches window 8m above ground. Find distance of foot of ladder from wall.
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In △ABC, AD ⊥ BC. Show that AB² + CD² = AC² + BD².
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CM and RN are medians of △ABC and △PQR respectively. If △ABC ~ △PQR, show △AMC ~ △PNR.
3 Marks
State and prove Basic Proportionality Theorem (Thales Theorem).
3 Marks
BL and CM are medians of right triangle ABC right angled at A. Prove 4(BL² + CM²) = 5BC².
3 Marks
In equilateral triangle ABC, D is a point on BC such that BD = 1/3 BC. Prove 9AD² = 7AB².
3 Marks
In an isosceles triangle ABC with AC = BC, if AB² = 2AC², prove that △ABC is right angled.
4 Marks
Case Study Scenario: A girl of height 90 cm is walking away from base of lamp-post at speed of 1.2 m/s. Lamp is 3.6 m above ground. Question: Find length of her shadow after 4 seconds.
4 Marks
Case Study Scenario: Vijay is preparing for Board exams. He sets up triangular study frame ABC where DE || BC. Question: If AD = 2.4 cm, DB = 3.6 cm, AE = 3.2 cm, find AC.
5 Marks
Prove that sum of squares of sides of a rhombus is equal to sum of squares of its diagonals.
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O is any point inside a rectangle ABCD. Prove OB² + OD² = OA² + OC².
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