CLASS 09 · CHAPTER 06

Lines and Angles
Practice Questions

20 curated NCERT questions to test your problem-solving skills. Click on "Show Solution & Answer" to check step-by-step working.

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Q1MCQ1 Mark

If two lines intersect each other, then vertically opposite angles are:

Q2MCQ1 Mark

An angle which is greater than 180° but less than 360° is called:

Q3MCQ1 Mark

Complement of angle 35° is:

Q4MCQ1 Mark

Supplement of angle 70° is:

Q5Assertion-Reason1 Mark

Assertion (A): Sum of angles on a straight line is 180°. Reason (R): A linear pair of angles are supplementary.

Q6Assertion-Reason1 Mark

Assertion (A): If two parallel lines are cut by a transversal, alternate interior angles are equal. Reason (R): Corresponding angles are equal when parallel lines are cut by transversal.

Q7Short Answer2 Marks

In figure, lines AB and CD intersect at O. If ∠AOC + ∠BOE = 70° and ∠BOD = 40°, find ∠BOE and reflex ∠COE.

ABCDEO40° (BOD)AOCBOE
Q8Short Answer2 Marks

In figure, ∠PQR = ∠PRQ. Prove that ∠PQS = ∠PRT.

SQRTP∠PQS∠PRT
Q9Short Answer2 Marks

If x + y = w + z, prove that AOB is a line.

ABOCDy (BOC)x (AOC)w (AOD)z (BOD)
Q10Short Answer2 Marks

In figure, AB || CD, ∠APQ = 50° and ∠PRD = 127°. Find x and y.

ABCDPQR50° (APQ)y (QPR)x (PQR)127° (PRD)
Q11Short Answer2 Marks

Angles of a triangle are in ratio 2 : 3 : 4. Find all three angles.

Q12Long Answer3 Marks

Prove that sum of three interior angles of a triangle is 180°.

Q13Long Answer3 Marks

In △ABC, sides AB and AC are produced to P and Q. Bisectors of ∠PBC and ∠QCB meet at O. Prove ∠BOC = 90° - 1/2 ∠A.

Q14Long Answer3 Marks

In figure, QT ⊥ PR, ∠TQR = 40° and ∠SPR = 30°. Find x and y.

PQRT (90°)S40° (TQR)30° (SPR)x (PRQ)y (QSP)
Q15Long Answer3 Marks

In figure, sides AB and AC of △ABC are produced to E and D. If bisectors BO and CO of ∠CBE and ∠BCD meet at O, find ∠BOC.

Q16Case Study4 Marks

Case Study Scenario: Two mirror strips PQ and RS are placed parallel to each other. An incident ray AB strikes PQ at B, reflects along BC and strikes RS at C, reflecting back along CD. Question: Prove that AB || CD.

P (Top Mirror)QR (Bottom Mirror)SABCDNormal 1Normal 2
Q17Case Study4 Marks

Case Study Scenario: A roof truss has AB || CD. Transversal line EF intersects AB at G and CD at H. Given ∠AGH = 3x + 15° and ∠GHD = 2x + 45°. Question: Find value of x and measure of ∠AGH.

ABCDEFGH3x + 15° (AGH)2x + 45° (GHD)
Q18PYQ5 Marks

In figure, AB || CD and CD || EF. Also EA ⊥ AB. If ∠BEF = 55°, find x, y and z.

ABCDEFxyz55° (BEF)
Q19PYQ5 Marks

In △ABC, ∠A - ∠B = 15° and ∠B - ∠C = 30°. Find all three angles.

Q20PYQ5 Marks

Side BC of △ABC is produced to D. Angle bisector of ∠A and line perpendicular to BC at E meet. Prove ∠AEB = 1/2 (∠B - ∠C).