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02
LESSON 02 · CLASS 10 MATHEMATICS (NCERT)

Area of Segment of a Circle

Understand minor and major segments of a circle, the segment area formula, and calculating triangle areas for 60°, 90°, and 120° angles.

01 · DEFINITION

What is a Segment of a Circle?

A segment of a circle is the portion of the circular region bounded by a chord and the corresponding arc.

GEOMETRIC DIAGRAM

Minor Segment vs Major Segment

OABMinor SegmentMajor Segment
Area of Minor Segment = Area of Sector OAPB - Area of △OAB
Area of Major Segment = Total Area of Circle - Area of Minor Segment
02 · TRIANGLE FORMULAS

Finding Area of △OAB

θ = 90°

Right-Angled Triangle (θ = 90°)

Area of △OAB = 1/2 × r × r = 1/2 r².
θ = 60°

Equilateral Triangle (θ = 60°)

Area of △OAB = (√3 / 4) r².
General θ

General Angle Formula

Area of △OAB = 1/2 r² sin θ.
03 · SOLVED NCERT EXAMPLE

Step-by-Step Problem Solving

EXAMPLE 1

A chord of a circle of radius 15 cm subtends an angle of 60° at the center. Find the area of the corresponding minor segment. (Use π = 3.14, √3 = 1.73)

Given: radius r = 15 cm, angle θ = 60°.

Step 1: Find Area of Sector OAPB:

Area of Sector = (60° / 360°) × 3.14 × 15 × 15
Area of Sector = (1 / 6) × 3.14 × 225 = 117.75 cm²

Step 2: Find Area of Equilateral △OAB (θ = 60°):

Area of △OAB = (√3 / 4) × r² = (1.73 / 4) × 225 = 97.31 cm²

Step 3: Area of Minor Segment:

Area = 117.75 - 97.31 = 20.44 cm²
04 · QUICK SUMMARY

Key Takeaways

01

Minor segment area = Area of Sector - Area of Triangle.

02

For 60° central angle, triangle is equilateral: Area = (√3/4) r².

03

For 90° central angle, triangle is right-angled: Area = (1/2) r².